(4x+7)(x^2-3x+9)=

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Solution for (4x+7)(x^2-3x+9)= equation:


Simplifying
(4x + 7)(x2 + -3x + 9) = 0

Reorder the terms:
(7 + 4x)(x2 + -3x + 9) = 0

Reorder the terms:
(7 + 4x)(9 + -3x + x2) = 0

Multiply (7 + 4x) * (9 + -3x + x2)
(7(9 + -3x + x2) + 4x * (9 + -3x + x2)) = 0
((9 * 7 + -3x * 7 + x2 * 7) + 4x * (9 + -3x + x2)) = 0
((63 + -21x + 7x2) + 4x * (9 + -3x + x2)) = 0
(63 + -21x + 7x2 + (9 * 4x + -3x * 4x + x2 * 4x)) = 0
(63 + -21x + 7x2 + (36x + -12x2 + 4x3)) = 0

Reorder the terms:
(63 + -21x + 36x + 7x2 + -12x2 + 4x3) = 0

Combine like terms: -21x + 36x = 15x
(63 + 15x + 7x2 + -12x2 + 4x3) = 0

Combine like terms: 7x2 + -12x2 = -5x2
(63 + 15x + -5x2 + 4x3) = 0

Solving
63 + 15x + -5x2 + 4x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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